C++回调涵数问题

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CODE:

typedef void (*DownloadFinishCallFunc)(DownloadTask* task, void* userData);
// 这里用typedef, 是用后者来替换前者,对吧?

DownloadFinishCallFunc callFunc; //这个很奇怪,DownloadFinishCallFunc明明是一个涵数指针.怎么这样定义呢
DownloadTask* curTask;
void* callFuncData;


SetFinishCallBack( DownloadManage::DownloadFinishedCallback, this );

void DownloadManage::DownloadFinishedCallback(DownloadThread::DownloadTask* task, void * data )
{
..............

}


void DownloadThread::SetFinishCallBack(DownloadFinishCallFunc func, void* userData)
{
callFunc = func;
callFuncData = userData;
}



当执行到这语句:
dlobject.m_dlThread->SetFinishCallBack( DownloadManage::DownloadFinishedCallback, this );

请问执行到这句之后会怎么调用.

我之前找了些资料:

void (*p) ();
void caller(void(*ptr)())
{
ptr(); /* 调用ptr指向的函数 */
}
void func();
int main()
{
p = func;
caller(p); /* 传递函数地址到调用者 */
}